Jun 16, 2013 · -2 int() is the constructor of class int. It will initialise your variable a to the default value of an integer, i.e. 0. Even if you don't call the constructor explicitly, the default …

Nov 25, 2013 · It is a pointer to function that returns int* and accepts int* and pointer to function that returns int* (and accepts undefined number of parameters; see comments).

A C++ question, I know int* foo (void) foo will return a pointer to int type how about int &foo (void) what does it return? Thank a lot!

Sep 25, 2010 · That second memory address, then, is expected to hold an int. Do note that, while you are declaring a pointer to an int, the actual int is not allocated. So it is valid to say int *i = …

Jan 28, 2012 · The internal representation of int and unsigned int is the same. Therefore, when you pass the same format string to printf it will be printed as the same. However, there are …

int* i, int * i, int*i, and int *i are all exactly equivalent. This stems from the C compiler (and it's compatible C like systems) ignoring white space in token stream generated during the process …

Jan 28, 2013 · int array[] = new int[10]; ? Both do work, and the result is exactly the same. Which one is quicker or better? Is there a style guide which recommends one?

Aug 24, 2016 · The question "what is the difference between int* and int []?" is a less trivial question than most people will think of: it depends on where it is used. In a declaration, like …

Dec 30, 2011 · int a = 5; int& b = a; b = 7; cout << a; prints out 7, and replacing int& b with int &b also prints out 7. In fact so does int&b and int & b. I tested this kind of behavior with a simple …

Dec 17, 2013 · │int││int││int││int││int││int││ └───┘└───┘└───┘└───┘└───┘└───┘└┄ Of course, there's no reason they can't all …