Proof: Limit of sinx/x as x approaches 0 with Squeeze Theorem | Calculus 1
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Proof: Limit of sinx/x as x approaches 0 with Squeeze Theorem | Calculus 1
We prove the limit of sinx/x as x goes to 0 equals 1 using the squeeze theorem and a geometric argument involving sectors and triangles on the unit circle. #calculus1 #apcalculus Join Wrath of Math to get exclusive videos, lecture notes, and more: https://www.youtube.com/channel/UCyEKvaxi8mt9FMc62MHcliw/join Squeeze Theorem Explained: (coming ...
53.1K viewsJun 14, 2023
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Including results for sin(x)/x.
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